Instructions
In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. Give answer
Solution
I : 4$$x^{2}$$ + 15x + 14 = 0
=> 4$$x^{2}$$ + 8x + 7x + 14 = 0
=> 4x ( x + 2) + 7 ( x + 2) = 0
=> (4x + 7) (x + 2) = 0
=> x = -7/4 , -2
II : 6$$y^{2}$$ + 10y = 0
=> y (6y + 10) = 0
=> y = 0 , -5/3
Since, 0 > -7/4 , -2 & -5/3 > -7/4 , -2
=> y > x
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