Instructions

In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. Give answer

Question 54

I. $$4x^2 + 15x + 14 = 0$$
II. $$6y^2 + 10y = 0$$

Solution

I : 4$$x^{2}$$ + 15x + 14 = 0

=> 4$$x^{2}$$ + 8x + 7x + 14 = 0

=> 4x ( x + 2) + 7 ( x + 2) = 0

=> (4x + 7) (x + 2) = 0

=> x = -7/4 , -2

II : 6$$y^{2}$$ + 10y = 0

=> y (6y + 10) = 0

=> y = 0 , -5/3

Since, 0 > -7/4 , -2 & -5/3 > -7/4 , -2

=> y > x

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I. $$4x^2 + 15x + 14 = 0$$II. $$6y^2 + 10y = 0$$