Question 55
An engineering student has to secure 24% marks to pass. He gets 61 and fails by 29 marks. What is the maximum marks for that exam?
Solution
Let maximum marks = $$100x$$
=> Passing marks = $$\frac{24}{100} \times 100x = 24x$$
According to ques,
=> $$24x - 29 = 61$$
=> $$24x = 61 + 29 = 90$$
=> $$x = \frac{90}{24} = \frac{15}{4}$$
$$\therefore$$ Maximum marks = $$100 \times \frac{15}{4} = 25 \times 15 = 375$$
=> Ans - (A)
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