Question 55

A piece of wire is in the shape of an equilateral triangle, each of whose sides is 4.4 cm. If it is re-bent to form a circular ring, the radius of the ring so formed $$ (taking\ \pi = \frac{22}{7})$$ is

Solution

Let radius of ring = $$r$$ cm and side of equilateral triangle = 4.4 cm

Circumference of circle = Perimeter of triangle

=> $$2\pi r=3s$$

=> $$2\times\frac{22}{7} r=3\times(4.4)$$

=> $$\frac{44r}{7}=3\times4.4$$

=> $$r=\frac{7\times3\times4.4}{44}$$

=> $$r=2.1$$ cm

=> Ans - (C)

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