What was the day of the week on $$14^{th}$$ June 2002?

Using Zeller's formula,
$$h = \left( q + \lfloor \frac{13(m+1)}{5} \rfloor + K + \lfloor \frac{K}{4} \rfloor + \lfloor \frac{J}{4} \rfloor - 2J \right) \pmod 7$$
Here 
q = day of month = 14
m = month = 4
K = year = 02
J = century = 20.
Plugging the values gives us:
$$h = \left( 14 + \lfloor \frac{13(6+1)}{5} \rfloor + 2 + \lfloor \frac{2}{4} \rfloor + \lfloor \frac{20}{4} \rfloor - 2(20) \right) \pmod 7$$
$$h = -1 \pmod 7$$
h = 6.
So, the day on $$14^{th}$$ June 2002 = Friday.