CAT 2022 Question Paper (Slot 1) Question 54
Question 54
The number of ways of distributing 20 identical balloons among 4 children such that each child gets some balloons but no child gets an odd number of balloons, is
Correct Answer: 84
Solution
Let the number of balloons each child received be 2a, 2b, 2c and 2d
2a + 2b + 2c + 2d = 20
a + b + c + d = 10
Each of them should get more than zero balloons.
Therefore, total number of ways = $$(n-1)_{C_{r-1}}=(10-1)_{C_{4-1}}=9_{C_3}=84$$
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Comments
Nishita Bhajipale
1 month ago
How its sloved 9c3
Chaitanya Patil
3 months, 3 weeks ago
why to divide by 6? and how a1+b1+c1+d1= 6?
Thasni K S
2 months, 1 week ago
divide by 6 because it's 9C3 and 9-3 is 6.
a1+a2+a3+a4= (a+b+c+d)-(4*1) = 10-4 = 6. (add the terms a1+1 = a, b1+1=b......and solve for a1+b1+c1+d1)
Sukhdev Kumawat
2 months, 3 weeks ago
Nothing understood worst sir
Ganesh Kumar
4 months ago
Teacher