Given, $$\operatorname{cosec}A=\frac{25}{7}$$
$$=$$> Â $$\sin A=\frac{7}{25}$$
$$\cos A=\sqrt{1-\sin^2A}$$
$$=\sqrt{1-\left(\frac{7}{25}\right)^2}$$
$$=\sqrt{1-\frac{49}{625}}$$
$$=\sqrt{\frac{625-49}{625}}$$
$$=\sqrt{\frac{576}{625}}$$
$$=\frac{24}{25}$$
$$\therefore\ \tan A=\frac{\sin A}{\cos A}=\frac{\frac{7}{25}}{\frac{24}{25}}=\frac{7}{24}$$
Hence, the correct answer is Option B
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