Question 54

Find $$x$$ if $$2 \sin^2 x - 1 = 0$$.

Solution

Given,

$$2 \sin^2 x - 1 = 0$$

$$=$$> $$2\sin^2x=1$$

$$=$$> $$\sin^2x=\frac{1}{2}$$

$$=$$> $$\sin x=\frac{1}{\sqrt{2}}$$

$$=$$> $$\sin x=\sin\frac{\pi\ }{4}$$

$$=$$> $$x=\frac{\pi}{4}$$

Hence, the correct answer is Option A

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