The numbers x, y, z are respectively proportional to 2, 3, 5 and the sum of x, y and z is 80. If the number z is given by the equation z = ax-8,
then a is
Let $$x=2k$$ , $$y=3k$$ and $$z=5k$$
Sum = $$(x+y+z)=80$$
=> $$2k+3k+5k=80$$
=> $$10k=80$$
=> $$k=\frac{80}{10}=8$$
Thus, $$x=2 \times 8=16$$ and $$z=40$$
Also, $$z=ax-8$$
=> $$40=16(a)-8$$
=> $$16a=40+8=48$$
=> $$a=\frac{48}{16}=3$$
=> Ans - (C)
Create a FREE account and get:
