Question 53

If tan 2A = cot(A-$$18^\circ$$) and 2A is an acute angle, then find 'A'.

tan 2A = cot(A-$$18^\circ$$)

$$\Rightarrow \cot\left(90\ -2A\right)$$ = cot(A-$$18^\circ$$)

$$\Rightarrow90$$ - 2A = A - 18

$$\Rightarrow$$A = 36

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