If tan 2A = cot(A-$$18^\circ$$) and 2A is an acute angle, then find 'A'.
tan 2A = cot(A-$$18^\circ$$)
$$\Rightarrow \cot\left(90\ -2A\right)$$ =Â cot(A-$$18^\circ$$)
$$\Rightarrow90$$ - 2A = A - 18
$$\Rightarrow$$A = 36
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