An urn contains 6 red, 4 blue, 2 green and 3 yellow marbles.
If four marbles are picked at random, what is the probability that one is green, two are blue and one is red ?
Number of ways of selecting 1 green, 2 blue and 1 red = $$^2C_1*^4C_2*^6C_1 = 2*6*6 = 72$$
Probability of selecting 1 green, 2 blue and 2 red = $$\frac{72}{^{15}C_4}$$ = $$\frac{24}{455}$$
Create a FREE account and get:
Detailed syllabus & Topic-wise Weightage
By proceeding you agree to create your account
Free CAT Syllabus PDF will be sent to your email address soon !!!
