Instructions

An urn contains 6 red, 4 blue, 2 green and 3 yellow marbles.

Question 52

If three marbles are picked at random, what is the probability that two are blue and one is yellow?

Solution
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Number of ways of selecting 2 blue urns and 1 yellow urn = $$^{4}C_2* ^{3}C_1$$ = 18

Probability of selecting 2 blue urns and 1 yellow urn  = $$\frac{18}{^{15}C_3}$$ = $$\frac{18}{455}$$

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