A rectangular paper of width 7 cm is rolled along its width and a cylinder of a radius 9 cm is formed. The volume of the cylinder is:(Take $$\pi = \frac{22}{7}$$)
A rectangular paper of width 7 cm is rolled along its width to form a cylinder, then the width of the paper became its height.
height of cylinder = 7 cm
the radius of the cylinder = 9 cm (as per the information given in the question.)
the volume of the cylinder =Â $$\pi\ \times\ \left(radius\right)^2\times\ height$$
=Â $$\frac{22}{7}\ \times\ \left(9\right)^2\times7$$
= $$\frac{22}{7}\ \times\ 81\times7$$
= $$22\times 81$$
=Â 1782Â $$cm^3$$
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