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A tangent PT is drawn to the circle $$x^2 + y^2 = 4$$ at the point $$P(\sqrt{3}, 1)$$. A Straight line L, perpendicular to PT is a tangent to the circle $$(x - 3)^2 + y^2 = 1$$
A common tangent of the two circles is
$$x = 4$$
$$y = 2$$
$$x + \sqrt{3}y = 4$$
$$x + 2\sqrt{2}y = 6$$
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