Question 52

What is the value of the square root of:
$$[\left\{(100  of  0.9 \times 0.8 - 7 \times 1.2 \div 0.2 + 5 \times 4 - 3 \times 2)\right\}\div 10 + 1.85]$$

Solution

= $$[\left\{(100\ of\ 0.9\times0.8-7\times1.2\div0.2+5\times4-3\times2)\right\}\div10+1.85]$$

= $$[\left\{(90\times0.8-7\times6+20-6)\right\}\div10+1.85]$$

= $$[\left\{(72-42+20-6)\right\}\div10+1.85]$$

= $$[\left\{44\right\}\div10+1.85]$$

= $$[4.4+1.85]$$

= 6.25

value of the square root of 6.25 = 2.5


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