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Let S be the area of the region enclosed by $$y = e^{-x^2}, y = 0, x = 0$$ and x = 1. Then
$$S \geq \frac{1}{e}$$
$$S \geq 1 - \frac{1}{e}$$
$$S \leq \frac{1}{4}\left(1 + \frac{1}{\sqrt{e}}\right)$$
$$S \leq \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{e}}\left(1 - \frac{1}{\sqrt{2}}\right)$$
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