Question 52
In Δ ABC, the height CD intersects AB at D. The midpoints of AB and BC are P and Q respectively. If AD = 8 cm and CD = 6 cm, then the length of PQ is?
Solution
AD = 8 cm, CD = 6 cm.
Then, AC = $$\sqrt{8^2+6^2} = \sqrt{64+36} = \sqrt{100} = 10$$ cm.
A straight line joining through mid points of two sides of a triangle is always parallel to the third side and half of the third side.
PQ = $$\dfrac{AC}{2} = \dfrac{10}{2} = 5$$ cm.
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