Question 52
If $$x - \frac{2}{x} = 15$$, then what is the value of $$\left(x^2 + \frac{4}{x^2}\right)$$?
Solution
$$x-\frac{2}{x}=15$$
Squaring on both sides,
$$x^2+\frac{4}{x^2}-2.x.\frac{2}{x}=225$$
$$x^2+\frac{4}{x^2}-4=225$$
$$x^2+\frac{4}{x^2}=229$$
Hence, the correct answer is Option A
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