Question 52

If $$\cosec \theta = \frac{13}{12}, then \sin \theta + \cos \theta - \tan \theta$$ is equal to:

Solution

$$\cosec \theta =\frac{H}{P}= \frac{13}{12}$$

H= 13, P= 12, B= 5 (We know that $$hypotnuse^2 = side^2 + side^2. So we will get B = 5$$

$$\sin \theta + \cos \theta - \tan \theta$$

$$\frac{P}{H}+\frac{B}{H}-\frac{P}{B}$$

$$\frac{12}{13}+\frac{5}{13}-\frac{12}{5}=-\frac{71}{65}$$

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