Consider the volumes of the following objects and arrange them in decreasing order:
i. A parallelepiped of length 5 cm, breadth 3 cm and height 4 cm
ii. A cube of each side 4 cm.
iii. A cylinder of radius 3 cm and length 3 cm
iv. A sphere of radius 3 cm

i. Volume of the parallelepiped of length 5 cm, breadth 3 cm and height 4 cm = 3*4*5 = 60 cm$$^3$$
ii. Volume  of the cube of each side 4 cm = 4^3 = 64 cm$$^3$$
iii.Volume  of the cylinder of radius 3 cm and length 3 cm = $$\pi*3^2*3$$ = 84.82 cm$$^3$$
iv. Volume  of the  sphere of radius 3 cm = $$4/3*\pi*3^3$$ = 113.09 cm$$^3$$

Therefore, we can say that volumes of the objects in decreasing order = iv,iii,ii,i.

Hence, option A is the correct answer.