A 900 metre long train crosses a 1200 metres long platform completely in 70 seconds. What is the speed of the train?
A 900 metre long train crosses a 1200 metres long platform completely in 70 seconds.
Speed of the train =Â $$\frac{length\ of\ train+length\ of\ platform}{time}$$
=Â $$\frac{900+1200}{70}$$
= $$\frac{2100}{70}$$
= 30 m/s
Here we need the speed in km/h. We know that 1 km = 1000 m and 1 hour = 3600Â seconds.
Speed of the train =Â $$30\times\frac{3600}{1000}$$ km/h
= $$3\times36$$ km/h
= 108Â km/h
Create a FREE account and get: