Which of the following statement is correct?

B₂ (10 Electrons)
$$\sigma_{1s}^2\ \sigma_{1s}^{*2}\ \sigma_{2s}^2\ \sigma_{2s}^{*2}\ \pi_{2p_x}^1=\pi_{2p_y}^1$$
It has two unpaired electrons and paramagnetic.

O₂ (16 Electrons)
$$\sigma_{1s}^2\ \sigma_{1s}^{*2}\ \sigma_{2s}^2\ \sigma_{2s}^{*2}\ \sigma_{2p_z}^2\ \pi_{2p_x}^2=\pi_{2p_y}^2\ \pi_{2p_x}^{*1}=\pi_{2p_y}^{*1}$$
It has two unpaired electrons and paramagnetic.

NO (15 Electrons)
$$\sigma_{1s}^2\ \sigma_{1s}^{*2}\ \sigma_{2s}^2\ \sigma_{2s}^{*2}\ \pi_{2p_x}^2=\pi_{2p_y}^2\ \sigma_{2p_z}^2\ \pi_{2p_x}^{*1}$$
It has one unpaired electron and paramagnetic.

C₂ (12 Electrons)
$$\sigma_{1s}^2\ \sigma_{1s}^{*2}\ \sigma_{2s}^2\ \sigma_{2s}^{*2}\ \pi_{2p_x}^2=\pi_{2p_y}^2$$
It has zero unpaired electrons and diamagnetic

Correct option: (C)