Solution
$$\frac{3(1-2sin^{2}x)}{cos^{2}x-sin^{2}x}$$
= $$\frac{3(1-2sin^{2}x)}{1-sin^{2}x-sin^{2}x}$$
($$\because sin^{2}x + cos^{2}x = 1$$)
= $$\frac{3(1-2sin^{2}x)}{1-2sin^{2}x}$$ = 3
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