SSC CGL 9th March 2020 Shift-3

Question 51

The value of $$\frac{3(1 - 2 \sin^{2}x)}{\cos^{2}x - \sin^{2}x}$$ is:

Solution

$$\frac{3(1-2sin^{2}x)}{cos^{2}x-sin^{2}x}$$

= $$\frac{3(1-2sin^{2}x)}{1-sin^{2}x-sin^{2}x}$$
($$\because sin^{2}x + cos^{2}x = 1$$)
= $$\frac{3(1-2sin^{2}x)}{1-2sin^{2}x}$$ = 3

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