Question 51

The following table shows the weight of 20 students:

The mode and median of the above data are, respectively:

Solution

Mode is the maximum number of students have the same weight. So here 6 students have 48 kg weight. Hence 48 will be the mode.

For Median, first, we need to arrange the given weight in the ascending order from left to right.

Total number of students = n = 20

Median = $$\frac{\left(\frac{n}{2}\right)th+\left(\frac{n}{2}+1\right)th}{2}$$

= $$\frac{\left(\frac{20}{2}\right)th+\left(\frac{20}{2}+1\right)th}{2}$$

= $$\frac{\left(10\right)th+\left(10+1\right)th}{2}$$

= $$\frac{\left(10\right)th+\left(11\right)th}{2}$$

= $$\frac{53+53}{2}$$

= 53


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