The compound interest on a certain sum of money at 11% for 2 years is ₹6963. Its simple interest (in ₹) at the same rate and for the same period is:

Given, Compound interest (C.I) = ₹6963

Rate (R%) = 11%, Time (T) = 2 years

Let the Pricipal Amount be P

$$=$$> $$6963=P\left(1+\frac{11}{100}\right)^2-P$$

$$=$$> $$6963=P\left(\frac{111}{100}\right)^2-P$$

$$=$$> $$6963=P\left(\frac{12321}{10000}\right)-P$$

$$=$$> $$6963=\frac{2321}{10000}P$$

$$=$$> $$P=3\times10000$$

$$=$$> $$P=₹30000$$

$$\therefore\ $$Simple Interest$$=\frac{PTR}{100}=\frac{30000\times2\times11}{100}=₹6600$$

Hence, the correct answer is Option B