The average marks obtained by a student in 9 subjects is 98. On subsequent verification it was found that the marks obtained by him in a subject was wrongly copied as 86 instead of 68. The correct average of the marks obtained by him is:
Given that the average marks obtained by a student in 9 subjects is 98
i.e; (total sum of marks)/9=98
therefore, total sum =98$$\times\ $$9=882
but given that marks obtained by him was wrongly copied as 86 instead of 68
therefore correct average is [882-(86-68)]/9
i.e; (882-18)/9
864/9=96
therefore the answer is option C
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