In the following questions two equations numbered I and II are given. You have to solve both the equations and
Give answer a: if x > y
Give answer b: if x ≥ Y
Give answer c: if x < y
Give answer d: if x ≤ Y
Give answer e: if x = y or the relationship between x and y cannot be established.
I. $$x^{2}=196$$
II. $$y^{2} +2y-48=0$$
I.$$x^{2} = 196$$
=> $$x = \sqrt{196}$$
=> $$x = 14 , -14$$
II.$$y^{2} + 2y - 48 = 0$$
=> $$y^2 + 8y - 6y - 48 = 0$$
=> $$y (y + 8) - 6 (y + 8) = 0$$
=> $$(y + 8) (y - 6) = 0$$
=> $$y = -8 , 6$$
$$\therefore$$ No relation can be established.
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