Question 51

A train, starting from rest, attains a velocity of 90 km/h in 5 minutes. Assuming that the acceleration is uniform, the distance travelled by the train during this time is:

Solution

Here, u ( initial velocity ) = 0
v ( Final Velocity ) = 90 km/h
t ( time taken ) =5 min

Distance s=??

First, bring all units same.

5 min = 5 × 60 s = 300 s

90 km/h = 90 × 5/18 = 25 m/s

v = u + at
25 = 0 + a(300)
25/300 = a
.083333 m/s² = a

s = ut + 1/2 ( at² )
s = (0)(3000) + 1/2 (0.08333)(300)(300)
s = (0.08333)(150)(300)
s = 3750 m=3.75km

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