$$(0.027)^2 \div (0.09)^5 \times (0.0081) = (0.3)^{?+4}$$

Solution

Expression : $$(0.027)^2 \div (0.09)^5 \times (0.0081) = (0.3)^{?+4}$$

=> $$(0.3)^{3 \times 2} \times \frac{1}{(0.3)^{2 \times 5}} \times (0.3)^{4} = (0.3)^{x + 4}$$

=> $$(0.3)^{6 - 10 + 4} = (0.3)^{x + 4}$$

=> $$(0.3)^0 = (0.3)^{x + 4}$$

=> $$x + 4 = 0$$

=> $$x = -4$$

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