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Question 50
A train passes a 50 m long platform in 14 sec and a man standing on a platform in 10 sec. The speed of the train is
Solution
Let the length of train = $$l$$ metre
$$\because speed = \frac{distance}{time}$$
=> $$\frac{l + 50}{14} = \frac{l}{10}$$
=> $$10l + 500 = 14l$$
=> $$14l - 10l = 4l = 500$$
=> $$l = \frac{500}{4} = 125$$ metre
$$\therefore$$ Speed of train = $$\frac{125}{10} = 12.5$$ m/s
= $$12.5 \times \frac{18}{5} = 2.5 \times 18$$
= $$45$$ km/hr
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