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A hyperbola, having the transverse axis of length $$2 \sin \theta$$, is confocal with the ellipse $$3x^2 + 4y^2 = 12$$. Then its equation is
$$x^2 \cosec^2 \theta - y^2 \sec^2 \theta = 1$$
$$x^2 \sec^2 \theta - y^2 \cosec^2 \theta = 1$$
$$x^2 \sin^2 \theta - y^2 \cos^2 \theta = 1$$
$$x^2 \cos^2 \theta - y^2 \sin^2 \theta = 1$$
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