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$$\lim_{x \rightarrow \frac{\pi}{4}}\frac{\int_{2}^{\sec^2 x}f(t)dt }{x^2 - \frac{\pi^2}{16}}$$ equals
$$\frac{8}{\pi}f(2)$$
$$\frac{2}{\pi}f(2)$$
$$\frac{2}{\pi}f\left(\frac{1}{2}\right)$$
$$4f(2)$$
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