Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Where A, B, C, D, E are distinct digits satisfying this addition fact, then E is
The addition reads $$ABC+CBA=DEDD$$, which simplifies to $$101(A+C)+20B=1011D+100E$$. Since the sum is at most 1998, $$D=1$$, and analyzing the equation modulo 20 shows $$A+C$$ must equal 11 for an integer solution, which forces $$E=2$$ (with $$B=5$$ and, for example, $$A=3$$, $$C=8$$).
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation