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In the sequence obtained by omitting the perfect squares from the sequence of natural numbers, $$2011^{\text{th}}$$ term is ____________
Correct Answer: 2056
Up to $$N$$ there are $$\left[\sqrt{N}\right]$$ perfect squares, so the number of non-squares up to $$N$$ is $$N - \left[\sqrt{N}\right]$$. For $$N = 2056$$, $$\left[\sqrt{2056}\right] = 45$$ and $$2056 - 45 = 2011$$, and 2056 is not a square. So the 2011th term is 2056.
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