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A body of mass $$50 \text{ kg}$$ is lifted to a height of $$20 \text{ m}$$ from the ground in the two different ways as shown in the figures. The ratio of work done against the gravity in both the respective cases, will be :
Work done against gravity is a state function that depends only on the change in vertical height, given by $$W = mgh$$.
$$W_1 = mgh$$
$$W_2 = mgh$$
$$\frac{W_1}{W_2} = \frac{mgh}{mgh} = 1 : 1$$
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