Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
If the height of a triangle is $$(4x^2 + 6)$$ unit and the base of that triangle is $$(3x^2 - 4)$$ unit, then the area of the triangle in sq. unit is
The area is $$\frac{1}{2}(4x^2 + 6)(3x^2 - 4) = \frac{1}{2}(12x^4 - 16x^2 + 18x^2 - 24)$$. This simplifies to $$\frac{1}{2}(12x^4 + 2x^2 - 24) = 6x^4 + x^2 - 12$$.
Was this solution helpful?
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.