Question 49
If a chord of length 24 cm is at a distance of 5 cm from centre, then find the radius of the circle.
Solution
it becomes a right angle triangle
chord = 24 cm
so
base of triangle = half of 24 = 12 cm
height = 5cm
apply pythagoras's thearom
hypotenuse = $$\sqrt(5^2 + 12^2)$$
= 13cm
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