Question 49

If a chord of length 24 cm is at a distance of 5 cm from centre, then find the radius of the circle.

Solution

it becomes a right angle triangle 

chord = 24 cm 

so

base of triangle = half of 24 = 12 cm

height = 5cm

apply pythagoras's thearom 

hypotenuse = $$\sqrt(5^2 + 12^2)$$

                  = 13cm


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