Train ‘A’ runs at a speed of 80 kmph and leaves station ‘X’ at 11.00 a.m. Train ‘B’ leaves station ‘X’ at 11.15 a.m.in the same direction, on the same day . At what speed train ‘B’ should run in order to catch train ‘A’ at station ‘Y’ located at a distance of 60 km?

Speed of train A = 80 km/h

Distance between station X and station Y = 60 km

Time taken by train A to reach station Y = $$\frac{60}{80}$$ hours = $$\frac{3}{4}$$ hours $$\frac{3}{4}\times$$60 minutes = 45 minutes

Since train B starts 15 min late, it should reach station Y in 30 minutes to catch train A at station Y.

Time taken by train B to reach station Y = 30 minutes = $$\frac{1}{2}$$ hour

$$\therefore\ $$Speed of train B = $$\frac{\text{Distance from station X to station Y}}{\text{Time}}$$ = $$\frac{60}{\frac{1}{2}}$$ = 120 km/h

Hence, the correct answer is Option A