Two lines $$L_1 : x = 5, \frac{y}{3 - \alpha} = \frac{z}{-2}$$ and $$L_2 : x = \alpha, \frac{y}{-1} = \frac{z}{2 - \alpha}$$ are coplanar. Then $$\alpha$$ can take value(s)

A

1

B

2

C

3

D

4