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The value of $$\int_{\sqrt{\ln 2}}^{\sqrt{\ln 3}} \frac{x \sin x^2}{\sin x^2 + \sin(\ln 6 - x^2)} dx $$ is
$$\frac{1}{4} \ln \frac{3}{2}$$
$$\frac{1}{2} \ln \frac{3}{2}$$
$$\ln \frac{3}{2}$$
$$\frac{1}{6} \ln \frac{3}{2}$$
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