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Let the straight line x = b divide the area enclosed by $$y = (1 - x^2), y = 0$$ and x = 0 into two parts $$R_1(0 \leq x \leq b)$$ and $$R_2(b \leq x leq 1)$$ such that $$R_1 - R_2 = \frac{1}{4}$$. Then b equals
$$\frac{3}{4}$$
$$\frac{1}{2}$$
$$\frac{1}{3}$$
$$\frac{1}{4}$$
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