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An unpolarized light of intensity $$I_0$$ passes through polarizer and then through a certain optically active solution and finally it goes to analyser. If the angle between analyser and polariser is 0$$^\circ$$ and intensity of light emerged from analyser is $$\frac{3}{8}I_0$$, the angle of rotation of the light by the solution with respect to analyser is _______ degrees.
Correct Answer: 30
When unpolarized light of intensity $$I_0$$ passes through a polarizer, its intensity reduces to half: $$I_1 = \frac{I_0}{2}$$
$$I_f = I_1 \cos^2\theta$$
$$\frac{3}{8}I_0 = \left(\frac{I_0}{2}\right) \cos^2\theta$$
$$\frac{3}{8} = \frac{1}{2} \cos^2\theta$$
$$\theta = 30^\circ$$
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