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The energy released when $$\frac{7}{17.13}$$ kg of $$^7_3$$Li is converted into $$^4_2$$He by proton bombardment is $$\alpha \times 10^{32}$$ eV. The value of $$\alpha$$ is _______. (Nearest integer)
(Mass of $$^7_3$$Li = 7.0183 u, mass of $$^4_2$$He = 4.004 u, mass of proton = 1.008 u and 1 u = 931 MeV/c$$^2$$ and Avogadro number = $$6.0 \times 10^{23}$$)
Correct Answer: 6
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