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In the previous question the distance travelled by the particle in $$12\text{ s}$$ is
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Distance is the total area under the graph taken positive. The areas are 3, 6 and 3 while moving forward and 3 while moving backward between 9 s and 12 s. Distance $$= 3 + 6 + 3 + 3 = 15\text{ m}$$.
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