Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Figure shows velocity time graph for a particle in motion. Displacement made by the particle in $$12\text{ s}$$ is
[image]
Displacement is the signed area under the velocity-time graph. From 0 to 3 s the area is $$\frac{1}{2} \times 3 \times 2 = 3$$, from 3 to 6 s it is $$3 \times 2 = 6$$, from 6 to 9 s it is $$3$$, and from 9 to 12 s it is $$-\frac{1}{2} \times 3 \times 2 = -3$$. Displacement $$= 3 + 6 + 3 - 3 = 9\text{ m}$$.
Was this solution helpful?
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.