[Solved] If \\alpha = \\int_{0}^{1} \\left(e^{9x + 3 \\tan^{-1}x}\\right)\\left(\\frac{12 + 9x^2}{1 + x^2}\\right) dx where \\tan^{-1}x takes only principal values, then the value of \\left(\\log_e |1 + \\alpha| - \\frac{3\\pi}{4}\\right) is - - JEE (Advanced) 2015 Paper-2