Question 46

Consider the above reaction, the major product P formed is:

Solution

Since the medium is acidic and the $$-OH$$ group is on the $$2^0$$ carbon, the reaction process can be $$SN_1$$. So there will be a carbocation intermediate formed. Rearrangement also takes place as follows:

The $$-Br$$ gets added to the carbon with the positive charge. Thus, the right option is B.

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Consider the above reaction, the major product P formed is:

Solution

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