Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 40 pages per hour. If Tom start reading a novel at $$4 : 30$$ and Jan begins reading an identical copy of the same book at $$5 : 20$$, at what time will they be reading the same page

Tom's speed = 30 pages/hr and Jan's speed = 40 pages/hr

Now, in 4:30 to 5:20 = 50 minutes, Tom has already read 25 pages.

Let $$t$$ minutes after 5:20, they will be reading the same page. Now, Tom is 25 pages ahead of Jan, and they are reading the same novel, thus effective speed = $$40-30=10$$ pages/hr

=> Time taken to catch up Tom = $$\frac{25}{10}=2.5$$ hours

$$\therefore$$ At 5:20 + 2:30 = 7:50, they will be reading the same page.

=> Ans - (D)