Given : m∠A = 60° and m∠B = 90°
=> In $$\triangle$$ ABC,
=> ∠A + ∠B + ∠C = 180°
=> ∠C + 60° + 90° = 180°
=> ∠C = 180° - 150° = 30°
To find : sec C.sin A
= $$sec(30^\circ) \times sin(60^\circ)$$
= $$\frac{2}{\sqrt3}\times\frac{\sqrt3}{2}=1$$
=> Ans - (D)
Create a FREE account and get: