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No. of $$\text{Na}^+$$ ions present in 100 ml of 1M solution of NaCl is ____
Correct Answer: 60220000000000000000000
100 mL of 1 M NaCl contains $$0.1$$ mol of NaCl, and hence $$0.1$$ mol of $$\text{Na}^+$$ ions. The number of ions is $$0.1 \times 6.022 \times 10^{23} = 6.022 \times 10^{22}$$.
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