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Question 44

In the following structure, the double bonds are marked as I, II, III and IV.

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Geometrical isomerism is not possible at the site(s):

Solution

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For geometric isomerism, each carbon of a $$C=C$$ bond must be bonded with two different groups. The carbon of the double bond $$I$$ is bonded with 2 methyl groups. Thus, geometric isomerism is not possible at the double bond $$I$$

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